Subnetting Calculation:
In CCNA Day 04 we had a glance about Subnetting, today we will learn how to calculate the IP range for the given IP Address
[01] Here we need to find out the 9th subnet for the IP 192 ● 168 ● 10 ● 0
Below is the simple formula to start calculating subnet range:
2x -2 = n
Here n = number of subnet
x = number of bits to borrow from Host bits
Step 01:
Here n = 9
To find out x value follow the calculation below:
2x -2 = n
2x -2 = 9
2x = 9 + 2
2x = 11 [ 24 = 16 ]
Hence 24 = 16 > 11
So x = 4
Step 02:
For Subnetting we need to Borrow bits from Host, hence wee need to Borrow the bit from left to right:
As the IP class range comes under Class C, so host is of 8 bit
Class C: Network ● Network ● Network ● Host
Left >>>>> 1 1 1 1 / 0 0 0 0 <<<<< Right
Hence Subnet is 255 ● 255 ● 255 ● 240
Step 03:
To find out 9th subnet we required to convert 9 to binary number
9 = 1001
To find out Network ID, in host all zero other than borrowed
To find out Minimum IP range in host all zero last one other than borrowed
To find out Maximum IP range in host all one last bit zero other than borrowed
To find out Broadcast IP in host all one other than borrowed bit
See the below calculation for more clarity
Network ID : 1 0 0 1 / 0 0 0 0 = 144
Min. IP Range : 1 0 0 1 / 0 0 0 1 = 145
Max. IP Range : 1 0 0 1 / 1 1 1 0 = 194
Broadcast IP : 1 0 0 1 / 1 1 1 1 = 195
Hence
Network IP = 192 ● 168 ● 10 ● 144
Min. IP = 192 ● 168 ● 10 ● 145
Max. IP = 192 ● 168 ● 10 ● 194
Broadcast IP = 192 ● 168 ● 10 ● 195
For Class B we need to borrow from 16 bit of Host Octet and
For Class A we need to borrow from 24 bit of Host Octet
If you feel any issues, contact me on ccnain30days@gmail.com
==========================================================
Related Articles:
CCNA Day 04 <<<<< Previous Articles = Next Articles >>>>> CCNA Day 06
==========================================================
Other Articles:
Binary Number System - Decimal Number System - Network Classes
==========================================================
In CCNA Day 04 we had a glance about Subnetting, today we will learn how to calculate the IP range for the given IP Address
[01] Here we need to find out the 9th subnet for the IP 192 ● 168 ● 10 ● 0
Below is the simple formula to start calculating subnet range:
2x -2 = n
Here n = number of subnet
x = number of bits to borrow from Host bits
Step 01:
Here n = 9
To find out x value follow the calculation below:
2x -2 = n
2x -2 = 9
2x = 9 + 2
2x = 11 [ 24 = 16 ]
Hence 24 = 16 > 11
So x = 4
Step 02:
For Subnetting we need to Borrow bits from Host, hence wee need to Borrow the bit from left to right:
As the IP class range comes under Class C, so host is of 8 bit
Class C: Network ● Network ● Network ● Host
Left >>>>> 1 1 1 1 / 0 0 0 0 <<<<< Right
Hence Subnet is 255 ● 255 ● 255 ● 240
Step 03:
To find out 9th subnet we required to convert 9 to binary number
9 = 1001
To find out Network ID, in host all zero other than borrowed
To find out Minimum IP range in host all zero last one other than borrowed
To find out Maximum IP range in host all one last bit zero other than borrowed
To find out Broadcast IP in host all one other than borrowed bit
See the below calculation for more clarity
Network ID : 1 0 0 1 / 0 0 0 0 = 144
Min. IP Range : 1 0 0 1 / 0 0 0 1 = 145
Max. IP Range : 1 0 0 1 / 1 1 1 0 = 194
Broadcast IP : 1 0 0 1 / 1 1 1 1 = 195
Hence
Network IP = 192 ● 168 ● 10 ● 144
Min. IP = 192 ● 168 ● 10 ● 145
Max. IP = 192 ● 168 ● 10 ● 194
Broadcast IP = 192 ● 168 ● 10 ● 195
For Class B we need to borrow from 16 bit of Host Octet and
For Class A we need to borrow from 24 bit of Host Octet
If you feel any issues, contact me on ccnain30days@gmail.com
==========================================================
Related Articles:
CCNA Day 04 <<<<< Previous Articles = Next Articles >>>>> CCNA Day 06
==========================================================
Other Articles:
Binary Number System - Decimal Number System - Network Classes
==========================================================
